x^2-2√3x+3/4=0
来源:百度知道 编辑:UC知道 时间:2024/09/23 19:10:55
根号下包括x
用公式法,要具体过程,步骤清楚些,好的我追加分
用公式法,要具体过程,步骤清楚些,好的我追加分
d
没办法解的,只有用计算机解!
没有公式的,一平方就4次了,怎么有公式啊?你题目是不是写错了?
-1/2*((6+35^(1/2))^(1/3)+1/(6+35^(1/2))^(1/3))^(1/2)*(-(6+35^(1/2))^(1/3)-1/(6+35^(1/2))^(1/3)+4/((6+35^(1/2))^(1/3)+1/(6+35^(1/2))^(1/3))^(1/2)*3^(1/2))^(1/2)+1/((6+35^(1/2))^(1/3)+1/(6+35^(1/2))^(1/3))^(1/2)*3^(1/2)
1/2*((6+35^(1/2))^(1/3)+1/(6+35^(1/2))^(1/3))^(1/2)*(-(6+35^(1/2))^(1/3)-1/(6+35^(1/2))^(1/3)+4/((6+35^(1/2))^(1/3)+1/(6+35^(1/2))^(1/3))^(1/2)*3^(1/2))^(1/2)+1/((6+35^(1/2))^(1/3)+1/(6+35^(1/2))^(1/3))^(1/2)*3^(1/2)
[x+2]/[x+1]-[x+4]/[x+3]-[x+3]/[x+2]+]x+5]/[x+4]
x+x^2+x^3+x^4+x^5+...+x^12=500/12
(x^2+2x-3)/(x^2-9)*(x^2-5x+6)/(3x^2-x-2)
x-1/x^2+3x+2+6/2+x-x^2-10-x/4-x^2
1+x+x^2+x^3=0 ,求x+x^2+x^3+...+x^2000
1/x-1 +1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+1/(x-4)(x-5)
已知道根号(X)+(1/根号X)=2,求根号(X/X^2+3X+1)-根号(X/X^2+9X+X)
X*X-2X-1=0 求2x*x*x-3*x*x-4*x+2
怎么解不等式(x^2+2x-2)/(3+2x-x^2)<x?
解不等式(x^2+2x-2)/(3+2x-x^2)<x